MathDB
۰Not so charming graph with degrees 2 and 3

Source: Iran Team selection test 2024 - P1

May 19, 2024
combinatorics

Problem Statement

Let GG be a simple graph with 1111 vertices labeled as v1,v2,...,v11v_{1} , v_{2} , ... , v_{11} such that the degree of v1v_1 equals to 22 and the degree of other vertices are equal to 33.If for any set AA of these vertices which A4|A| \le 4 , the number of vertices which are adjacent to at least one verex in AA and are not in AA themselves is at least equal to A|A| , then find the maximum possible number for the diameter of GG. (The distance between two vertices of graph is the number of edges of the shortest path between them and the diameter of a graph , is the largest distance between arbitrary pairs in V(G)V(G). )
Proposed by Alireza Haqi