MathDB
1994 AJHSME Problem 7

Source:

July 9, 2011

Problem Statement

If A=60\angle A = 60^\circ , E=40\angle E = 40^\circ and C=30\angle C = 30^\circ , then BDC=\angle BDC =
[asy] pair A,B,C,D,EE; A = origin; B = (2,0); C = (5,0); EE = (1.5,3); D = (1.75,1.5); draw(A--C--D); draw(B--EE--A); dot(A); dot(B); dot(C); dot(D); dot(EE); label("AA",A,SW); label("BB",B,S); label("CC",C,SE); label("DD",D,NE); label("EE",EE,N); [/asy]
(A) 40(B) 50(C) 60(D) 70(E) 80\text{(A)}\ 40^\circ \qquad \text{(B)}\ 50^\circ \qquad \text{(C)}\ 60^\circ \qquad \text{(D)}\ 70^\circ \qquad \text{(E)}\ 80^\circ