MathDB
exists c : b_n=c a_n. a_{n+2}=a_n+a_{n+1}, b_{n+2}=b_n+b_{n+1}, a_n / b_n

Source: 2021 Francophone MO Seniors p1

April 3, 2021
Sequencenumber theorydividesrecurrence relationFrancophone

Problem Statement

Let a1,a2,a3,a_1,a_2,a_3,\ldots and b1,b2,b3,b_1,b_2,b_3,\ldots be positive integers such that an+2=an+an+1a_{n+2} = a_n + a_{n+1} and bn+2=bn+bn+1b_{n+2} = b_n + b_{n+1} for all n1n \ge 1. Assume that ana_n divides bnb_n for infinitely many values of nn. Prove that there exists an integer cc such that bn=canb_n = c a_n for all n1n \ge 1.