MathDB
x^a + x^d>= x^b + x^c , for x>0 if a>b>c>d >= q 0 and a + d = b + c

Source: 1978 Swedish Mathematical Competition p1

March 26, 2021
inequalitiesalgebra

Problem Statement

Let a,b,c,da,b,c,d be real numbers such that a>b>c>d0a>b>c>d\geq 0 and a+d=b+ca + d = b + c. Show that xa+xdxb+xc x^a + x^d \geq x^b + x^c for x>0x>0.