MathDB
f''(0) , (...((x - 2)^2 - 2)^2 - 2)^2..- VI Soros Olympiad 1999-00 Round 1 11.2

Source:

May 21, 2024
algebraderivativecalculus

Problem Statement

Let f(x)=(...((x2)22)22)2...2)2f(x) = (...((x - 2)^2 - 2)^2 - 2)^2... - 2)^2 (here there are nn brackets ()( )). Find f(0)f''(0)