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Prove HE = HF

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February 23, 2009
geometrycircumcirclecongruent trianglesangle bisectorgeometry unsolved

Problem Statement

Let ABC ABC is a triangle, let H H is orthocenter of △ABC \triangle ABC, let M M is midpoint of BC BC. Let (d) (d) is a line perpendicular with HM HM at point H H. Let (d) (d) meet AB,AC AB, AC at E,F E, F respectively. Prove that HE \equal{}HF.
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