Let f(n)=105+35(21+5)n+105−35(21−5)n. Then f(n+1)−f(n−1), expressed in terms of f(n), equals:<spanclass=′latex−bold′>(A)</span>21f(n)<spanclass=′latex−bold′>(B)</span>f(n)<spanclass=′latex−bold′>(C)</span>2f(n)+1<spanclass=′latex−bold′>(D)</span>f2(n)<spanclass=′latex−bold′>(E)</span>21(f2(n)−1)