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Exists c, f'(c)=...

Source: Moldavian MO 2006

March 19, 2006
functionlimitreal analysisreal analysis unsolved

Problem Statement

Function f:[a,b]Rf: [a,b]\to\mathbb{R}, 0<a<b0<a<b is continuous on [a,b][a,b] and differentiable on (a,b)(a,b). Prove that there exists c(a,b)c\in(a,b) such that f(c)=1ac+1bc+1a+b. f'(c)=\frac1{a-c}+\frac1{b-c}+\frac1{a+b}.