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n + (n+1) + (n+2) +...+ (n+m) = 1000

Source: 1964 Swedish Mathematical Competition p2

March 21, 2021
number theoryDiophantine equationdiophantine

Problem Statement

Find all positive integers m,nm, n such that n+(n+1)+(n+2)+...+(n+m)=1000n + (n+1) + (n+2) + ...+ (n+m) = 1000.
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