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2019 MMATHS Mathathon Rounds 5-7 Math Majors of America Tournament for HS

Source:

February 25, 2022
algebrageometrycombinatoricsnumber theoryMMATHS

Problem Statement

Round 5
p13. Suppose ABC\vartriangle ABC is an isosceles triangle with AB=BC\overline{AB} = \overline{BC}, and XX is a point in the interior of ABC\vartriangle ABC. If mABC=94om \angle ABC = 94^o, mABX=17om\angle ABX = 17^o, and mBAX=13om\angle BAX = 13^o, then what is mBXCm\angle BXC (in degrees)?
p14. Find the remainder when n=120191+2n+4n2+8n3\sum^{2019}_{n=1} 1 + 2n + 4n^2 + 8n^3 is divided by 20192019.
p15. How many ways can you assign the integers 11 through 1010 to the variables a,b,c,d,e,f,g,h,ia, b, c, d, e, f, g, h, i, and jj in some order such that a<b<c<d<e,f<g<h<ia < b < c < d < e, f < g < h < i, a<g,b<h,c<ia < g, b < h, c < i, f<b,g<cf < b, g < c, and h<dh < d?
Round 6
p16. Call an integer nn equi-powerful if nn and n2n^2 leave the same remainder when divided by 1320. How many integers between 11 and 13201320 (inclusive) are equi-powerful?
p17. There exists a unique positive integer j10j \le 10 and unique positive integers njn_j , nj+1n_{j+1}, ......, n10n_{10} such that jnj<nj+1<...<n10j \le n_j < n_{j+1} < ... < n_{10} and (n1010)+(n99)+...+(njj)=2019.{n_{10} \choose 10}+ {n_9 \choose 9}+ ... + {n_j \choose j}= 2019. Find nj+nj+1+...+n10n_j + n_{j+1} + ... + n_{10}.
p18. If nn is a randomly chosen integer between 11 and 390390 (inclusive), what is the probability that 26n26n has more positive factors than 6n6n?
Round 7
p19. Suppose SS is an nn-element subset of {1,2,3,...,2019}\{1, 2, 3, ..., 2019\}. What is the largest possible value of nn such that for every 2kn2 \le k \le n, kk divides exactly n1n - 1 of the elements of SS?
p20. For each positive integer nn, let f(n)f(n) be the fewest number of terms needed to write nn as a sum of factorials. For example, f(28)=3f(28) = 3 because 4!+2!+2!=284! + 2! + 2! = 28 and 28 cannot be written as the sum of fewer than 33 factorials. Evaluate f(1)+f(2)+...+f(720)f(1) + f(2) + ... + f(720).
p21. Evaluate n=1ϕ(n)101n1\sum_{n=1}^{\infty}\frac{\phi (n)}{101^n-1} , where ϕ(n)\phi (n) is the number of positive integers less than or equal to n that are relatively prime to nn.
PS. You should use hide for answers. Rounds 1-4 have been posted [url=https://artofproblemsolving.com/community/c4h2788993p24519281]here. Collected [url=https://artofproblemsolving.com/community/c5h2760506p24143309]here.