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compare 2014^{9^{9^a}}, 2015^{a^{a^9}} if a=123456789

Source: 2015 Moldova JBMO TST p1

February 25, 2021
algebra

Problem Statement

Ler aa be the number 123456789123456789. Compare the numbers 201499a,2015aa92014^{9^{9^a}}, 2015^{a^{a^9}}