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Difference=gcd

Source: Singapore MO 2011 senior round 2 Q2

June 25, 2011
number theorygreatest common divisorleast common multiplenumber theory proposed

Problem Statement

Determine if there is a set SS of 2011 positive integers so that for every pair m,nm,n of distinct elements of SS, mn=(m,n)|m-n|=(m,n). Here (m,n)(m,n) denotes the greatest common divisor of mm and nn.