MathDB
1/R_12 +1/R_23+1/R_34+1/R_14 = 2 (1/R_13+1/R_24 )

Source: Norwegian Mathematical Olympiad 2012 - Abel Competition p2

September 4, 2019
geometrytangential quadrilateralcirclestanegntscircle

Problem Statement

(a)Two circles S1S_1 and S2S_2 are placed so that they do not overlap each other, neither completely nor partially. They have centres in O1O_1 and O2O_2, respectively. Further, L1L_1 and M1M_1 are different points on S1S_1 so that O2L1O_2L_1 and O2M1O_2M_1 are tangent to S1S_1, and similarly L2L_2 and M2M_2 are different points on S2S_2 so that O1L2O_1L_2 and O1M2O_1M_2 are tangent to S2S_2. Show that there exists a unique circle which is tangent to the four line segments O2L1,O2M1,O1L2O_2L_1, O_2M_1, O_1L_2, and O1M2O_1M_2.
(b) Four circles S1,S2,S3S_1, S_2, S_3 and S4S_4 are placed so that none of them overlap each other, neither completely nor partially. They have centres in O1,O2,O3O_1, O_2, O_3, and O4O_4, respectively. For each pair (Si,Sj)(S_i, S_j ) of circles, with 1i<j41 \le i < j \le 4, we find a circle SijS_{ij} as in part a. The circle SijS_{ij} has radius RijR_{ij} . Show that 1R12+1R23+1R34+1R14=2(1R13+1R24)\frac{1}{R_{12}} + \frac{1}{R_{23}}+\frac{1}{R_{34}}+\frac{1}{R_{14}}= 2 \left(\frac{1}{R_{13}} +\frac{1}{R_{24}}\right)