MathDB
Combinatorium Ultimatum --- Prove that n is 2 mod 4

Source: India TST 2016 Day 1 Problem 3

July 22, 2016
combinatorics

Problem Statement

Let nn be a natural number. A sequence x1,x2,,xn2x_1,x_2, \cdots ,x_{n^2} of n2n^2 numbers is called n<spanclass=latexitalic>good</span>n-<span class='latex-italic'>good</span> if each xix_i is an element of the set {1,2,,n}\{1,2,\cdots ,n\} and the ordered pairs (xi,xi+1)\left(x_i,x_{i+1}\right) are all different for i=1,2,3,,n2i=1,2,3,\cdots ,n^2 (here we consider the subscripts modulo n2n^2). Two nn-good sequences x1,x2,,xn2x_1,x_2,\cdots ,x_{n^2} and y1,y2,,yn2y_1,y_2,\cdots ,y_{n^2} are called <spanclass=latexitalic>similar</span><span class='latex-italic'>similar</span> if there exists an integer kk such that yi=xi+ky_i=x_{i+k} for all i=1,2,,n2i=1,2,\cdots,n^2 (again taking subscripts modulo n2n^2). Suppose that there exists a non-trivial permutation (i.e., a permutation which is different from the identity permutation) σ\sigma of {1,2,,n}\{1,2,\cdots ,n\} and an nn- good sequence x1,x2,,xn2x_1,x_2,\cdots,x_{n^2} which is similar to σ(x1),σ(x2),,σ(xn2)\sigma\left(x_1\right),\sigma\left(x_2\right),\cdots ,\sigma\left(x_{n^2}\right). Show that n2(mod4)n\equiv 2\pmod{4}.