MathDB
(x+2)^4/x^3 - (x+2)^2/2x >= - x/16 (Greece Junior 2020 p1)

Source:

March 16, 2020
inequalitiesalgebra

Problem Statement

Solve in real numbers (x+2)4x3(x+2)22xx16\frac{(x+2)^4}{x^3}-\frac{(x+2)^2}{2x}\ge - \frac{x}{16}