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paper folding a pentagon (May Olympiad 2007 L1)

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May 11, 2019
geometrypaperrectanglepentagon

Problem Statement

You have a paper pentagon, ABCDEABCDE, such that AB=BC=3AB = BC = 3 cm, CD=DE=5CD = DE= 5 cm, EA=4EA = 4 cm, ∠ABC=100o\angle ABC = 100^o ,∠CDE=80o \angle CDE = 80^o. You have to divide the pentagon into four triangles, by three straight cuts, so that with the four triangles assemble a rectangle, without gaps or overlays. (The triangles can be rotated and / or turned around.)
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