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VTRMC
2017 VTRMC
3
2017 VTRMC #3
2017 VTRMC #3
Source:
August 8, 2018
Problem Statement
Let
A
B
C
ABC
A
BC
be a triangle and let
P
P
P
be a point in its interior. Suppose
∠
B
A
P
=
1
0
∘
,
∠
A
B
P
=
2
0
∘
,
∠
P
C
A
=
3
0
∘
\angle B A P = 10 ^ { \circ } , \angle A B P = 20 ^ { \circ } , \angle P C A = 30 ^ { \circ }
∠
B
A
P
=
1
0
∘
,
∠
A
BP
=
2
0
∘
,
∠
PC
A
=
3
0
∘
and
∠
P
A
C
=
4
0
∘
\angle P A C = 40 ^ { \circ }
∠
P
A
C
=
4
0
∘
. Find
∠
P
B
C
\angle P B C
∠
PBC
.
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