MathDB
BT = 2PT wanted, 40-70-70 triangle (2010 Romania District VII P3)

Source:

May 19, 2020
anglesgeometryisoscelesequal segments

Problem Statement

Consider triangle ABCABC with AB=ACAB = AC and A=40o\angle A = 40 ^o. The points SS and TT are on the sides ABAB and BCBC, respectively, so that BAT=BCS=10o\angle BAT = \angle BCS= 10 ^o. The lines ATAT and CSCS intersect at point PP. Prove that BT=2PTBT = 2PT.