MathDB
Proving collinearity

Source: Bulgarian IMO TST 2008, Day 2, Problem 2

July 8, 2013
geometrycircumcirclegeometric transformationhomothetytrigonometrypower of a pointradical axis

Problem Statement

In the triangle ABCABC, AMAM is median, MBCM \in BC, BB1BB_{1} and CC1CC_{1} are altitudes, C1ABC_{1} \in AB, B1ACB_{1} \in AC. The line through AA which is perpendicular to AMAM cuts the lines BB1BB_{1} and CC1CC_{1} at points EE and FF, respectively. Let kk be the circumcircle of EFM\triangle EFM. Suppose also that k1k_{1} and k2k_{2} are circles touching both EFEF and the arc EFEF of kk which does not contain MM. If PP and QQ are the points at which k1k_{1} intersects k2k_{2}, prove that PP, QQ, and MM are collinear.