MathDB
Chisinau MO p100 1975 R1 X sin^3x+sin^32x +sin^33x=(sinx+sin2x+sin3x)^3

Source:

March 16, 2021
algebratrigonometry

Problem Statement

Solve the equation: sin3x+sin32x+sin33x=(sinx+sin2x+sin3x)3\sin ^3x+\sin ^32x+\sin ^33x=(\sin x + \sin 2x + \sin 3x)^3.