MathDB
Romanian NMO 2021 inequality

Source:

April 25, 2021
inequalitiesalgebra

Problem Statement

If a,b,c>0,a+b+c=1a,b,c>0,a+b+c=1,then:
1abc+4a2+b2+c213ab+bc+ca\frac{1}{abc}+\frac{4}{a^{2}+b^{2}+c^{2}}\geq\frac{13}{ab+bc+ca}