Convex hexagon A1A2A3A4A5A6 lies in the interior of convex hexagon B1B2B3B4B5B6 such that A1A2∥B1B2, A2A3∥B2B3,..., A6A1∥B6B1. Prove that the areas of simple hexagons A1B2A3B4A5B6 and B1A2B3A4B5A6 are equal. (A simple hexagon is a hexagon which does not intersect itself.)Proposed by Hirad Aalipanah - Mahdi Etesamifard