MathDB
[(2^1+3^1)...(2^{2048}+3^{2048})+2^{4096}]/3^{4096}

Source: 15th -a QEDMO problem 11 (19. - 22. 10. 2017) https://artofproblemsolving.com/community/c1512515_qedmo_2005

May 30, 2021
Sumalgebra

Problem Statement

Calculate (21+31)(22+32)(24+34)(28+38)...(22048+32048)+2409634096\frac{(2^1+3^1)(2^2+3^2)(2^4+3^4)(2^8+3^8)...(2^{2048}+3^{2048})+2^{4096}}{3^{4096}}