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Leiden quadruple (p, a, b, c) with p + 2 = (a+b+c)/3

Source: Dutch NMO 2014 p4

September 7, 2019
number theoryprimedivisibleInequalitydiophantine

Problem Statement

A quadruple (p,a,b,c)(p, a, b, c) of positive integers is called a Leiden quadruple if - pp is an odd prime number, - a,ba, b, and cc are distinct and - ab+1,bc+1ab + 1, bc + 1 and ca+1ca + 1 are divisible by pp. a) Prove that for every Leiden quadruple (p,a,b,c)(p, a, b, c) we have p+2a+b+c3p + 2 \le \frac{a+b+c}{3} . b) Determine all numbers pp for which a Leiden quadruple (p,a,b,c)(p, a, b, c) exists with p+2=a+b+c3p + 2 = \frac{a+b+c}{3}