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1
3^a+2^b+2015=3 c! for integers a,b,c>=0
3^a+2^b+2015=3 c! for integers a,b,c>=0
Source: 2015 Belarus TST 1.1
November 5, 2020
number theory
Diophantine equation
diophantine
Problem Statement
Solve the equation in nonnegative integers
a
,
b
,
c
a,b,c
a
,
b
,
c
:
3
a
+
2
b
+
2015
=
3
c
!
3^a+2^b+2015=3c!
3
a
+
2
b
+
2015
=
3
c
!
I.Gorodnin
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