Today's calculation of Integral 235
Source: Tsukuba University entrance exam 1994
October 10, 2007
calculusintegrationfunctiontrigonometrylimitcalculus computations
Problem Statement
Show that a function f(x)\equal{}\int_{\minus{}1}^1 (1\minus{}|\ t\ |)\cos (xt)\ dt is continuous at x\equal{}0.