MathDB
f (x) \ne 0 and f (x+2) = f (x-1) f (x+5) => f (x+18) = f (x)

Source: 1998 Estonia National Olympiad Final Round grade 11 p3

March 11, 2020
functionperiodicfunctional equationfunctionalalgebra

Problem Statement

A function ff satisfies the conditions f(x)0f (x) \ne 0 and f(x+2)=f(x1)f(x+5)f (x+2) = f (x-1) f (x+5) for all real x. Show that f(x+18)=f(x)f (x+18) = f (x) for any real xx.