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|2^{1/3} - m/n| > c/n^3

Source: 1998 Swedish Mathematical Competition p6

April 2, 2021
inequalitiesalgebra

Problem Statement

Show that for some c>0c > 0, we have 23mn>cn3\left|\sqrt[3]{2} - \frac{m}{n}\right | > \frac{c}{n^3} for all integers m,nm, n with n1n \ge 1.