If the integers m,n,k hold the equation 221m+247n+323k=2001, what is the smallest possible value of k greater than 100?<spanclass=′latex−bold′>(A)</span>124<spanclass=′latex−bold′>(B)</span>111<spanclass=′latex−bold′>(C)</span>107<spanclass=′latex−bold′>(D)</span>101<spanclass=′latex−bold′>(E)</span>None of the preceding