Transforming Polynomial
Source:
June 13, 2009
algebrapolynomialVieta
Problem Statement
The roots of Ax^2 \plus{} Bx \plus{} C \equal{} 0 are and . For the roots of
x^2 \plus{} px \plus{} q \equal{} 0
to be and , must equal:
(A)\ \frac{B^2 \minus{} 4AC}{A^2}\qquad
(B)\ \frac{B^2 \minus{} 2AC}{A^2}\qquad
(C)\ \frac{2AC \minus{} B^2}{A^2}\qquad \\
(D)\ B^2 \minus{} 2C\qquad
(E)\ 2C \minus{} B^2