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2005 AIME Problems
9
Working with i
Working with i
Source:
November 13, 2005
trigonometry
floor function
modular arithmetic
complex numbers
Problem Statement
For how many positive integers
n
n
n
less than or equal to
1000
1000
1000
is
(
sin
t
+
i
cos
t
)
n
=
sin
n
t
+
i
cos
n
t
(\sin t + i \cos t)^n=\sin nt + i \cos nt
(
sin
t
+
i
cos
t
)
n
=
sin
n
t
+
i
cos
n
t
true for all real
t
t
t
?
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