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Bosnia and Herzegovina TST 2000 Day 1 Problem 2

Source: Bosnia and Herzegovina Team Selection Test 2000

September 19, 2018
geometrycircumcircleiff

Problem Statement

Let SS be a point inside triangle ABCABC and let lines ASAS, BSBS and CSCS intersect sides BCBC, CACA and ABAB in points XX, YY and ZZ, respectively. Prove that BXCXAX2+CYAYBY2+AZBZCZ2=Rr1\frac{BX\cdot CX}{AX^2}+\frac{CY\cdot AY}{BY^2}+\frac{AZ\cdot BZ}{CZ^2}=\frac{R}{r}-1 iff SS is incenter of ABCABC