MathDB
inequality over (0,1), with x_(i+1)-x_i<=h

Source: VJIMC 2006 1.1

June 28, 2021
inequalities

Problem Statement

Given real numbers 0=x1<x2<<x2n<x2n+1=10=x_1<x_2<\ldots<x_{2n}<x_{2n+1}=1 such that xi+1xihx_{i+1}-x_i\le h for 1i2n1\le i\le2n, show that 1h2<i=1nx2i(x2i+1x2i1)<1+h2.\frac{1-h}2<\sum_{i=1}^nx_{2i}(x_{2i+1}-x_{2i-1})<\frac{1+h}2.