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Source: 2017 AMC 10B #15

February 16, 2017
geometryrectangleAMCAMC 10AMC 10 B2017 AMC 10B

Problem Statement

Rectangle ABCDABCD has AB=3AB=3 and BC=4.BC=4. Point EE is the foot of the perpendicular from BB to diagonal AC‾.\overline{AC}. What is the area of △ADE?\triangle ADE?
<spanclass=′latex−bold′>(A)</span> 1<spanclass=′latex−bold′>(B)</span> 4225<spanclass=′latex−bold′>(C)</span> 2815<spanclass=′latex−bold′>(D)</span> 2<spanclass=′latex−bold′>(E)</span> 5425<span class='latex-bold'>(A)</span> \text{ 1} \qquad <span class='latex-bold'>(B)</span> \text{ }\frac{42}{25} \qquad <span class='latex-bold'>(C)</span> \text{ }\frac{28}{15} \qquad <span class='latex-bold'>(D)</span> \text{ 2} \qquad <span class='latex-bold'>(E)</span> \text{ }\frac{54}{25}
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