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Bulgaria Contests
Bulgaria Team Selection Test
2003 Bulgaria Team Selection Test
6
Solve !
Solve !
Source: Bulgaria TST 2003 P6
September 1, 2012
number theory proposed
number theory
Problem Statement
In natural numbers
m
,
n
m,n
m
,
n
Solve :
n
(
n
+
1
)
(
n
+
2
)
(
n
+
3
)
=
m
(
m
+
1
)
2
(
m
+
2
)
3
(
m
+
3
)
4
n(n+1)(n+2)(n+3)=m(m+1)^2(m+2)^3(m+3)^4
n
(
n
+
1
)
(
n
+
2
)
(
n
+
3
)
=
m
(
m
+
1
)
2
(
m
+
2
)
3
(
m
+
3
)
4
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