MathDB

Let

H

be the intersection of altitudes in triangle

ABC

. If \angle B\equal{}\angle C\equal{}\alpha and

O

is the center of circle passing through

A

H

and

C

, then find

\angle HOC

in terms of

\alpha

.
(A)\ 90{}^\circ \minus{}\alpha \qquad(B)\ 90{}^\circ \plus{}\frac{\alpha }{2} \qquad(C)\ 180{}^\circ \minus{}\alpha \\ \qquad(D)\ 180{}^\circ \minus{}\frac{\alpha }{2} \qquad(E)\ 180{}^\circ \minus{}2\alpha

Problem Statement