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Today's calculation of Integral 810

Source: 2012 Keio University entrance exam/Science and Technology

March 23, 2012
calculusintegrationfunctioncalculus computations

Problem Statement

Given the functions f(x)=xex+2x∫02∣g(t)∣dt−1, g(x)=x2−x∫01f(t)dtf(x)=xe^{x}+2x\int_0^2 |g(t)|dt-1,\ g(x)=x^2-x\int_0^1 f(t)dt, evaluate ∫02∣g(t)∣dt.\int_0^2 |g(t)|dt.
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