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Value of fraction

Source: 1964 AHSME Problem 19

August 23, 2013
AMC

Problem Statement

If 2x−3y−z=02x-3y-z=0 and x+3y−14z=0x+3y-14z=0, z≠0z \neq 0, the numerical value of x2+3xyy2+z2\frac{x^2+3xy}{y^2+z^2} is:
<spanclass=′latex−bold′>(A)</span> 7<spanclass=′latex−bold′>(B)</span> 2<spanclass=′latex−bold′>(C)</span> 0<spanclass=′latex−bold′>(D)</span> −20/17<spanclass=′latex−bold′>(E)</span> −2 <span class='latex-bold'>(A)</span>\ 7\qquad<span class='latex-bold'>(B)</span>\ 2\qquad<span class='latex-bold'>(C)</span>\ 0\qquad<span class='latex-bold'>(D)</span>\ -20/17\qquad<span class='latex-bold'>(E)</span>\ -2
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