Ratios
Source: Indian Postal Coaching 2005; 18-th Korean Mathematical Olympiad 2005, final round, problem 4
October 27, 2005
ratiogeometrycircumcirclegeometry unsolved
Problem Statement
In the following, the point of intersection of two lines and will be abbreviated as .
Suppose is a triangle in which \angle A \equal{} 90^{\circ} and . Let be the circumcircle of the triangle . Let and be the tangents to the circle at and , respectively.
Let BC \cap l_{A} \equal{} S and AC \cap l_{B} \equal{} D. Furthermore, let AB \cap DS \equal{} E, and let CE \cap l_{A} \equal{} T. Denote by the foot of the perpendicular from on . Denote by the point of intersection of the line with the circle (different from ). Denote by be the point of intersection of the line with the circle (different from ). Finally, define U \equal{} BR \cap l_{A}. Prove that
\frac {SU \cdot SP}{TU \cdot TP} \equal{} \frac {SA^{2}}{TA^{2}}.