MathDB
Triangle

Source: Indonesia 2nd Round 2008

June 25, 2008
geometrytrigonometrygeometry unsolved

Problem Statement

Given triangle ABC ABC. The incircle of triangle ABC ABC is tangent to BC,CA,AB BC,CA,AB at D,E,F D,E,F respectively. Construct point G G on EF EF such that DG DG is perpendicular to EF EF. Prove that \frac{FG}{EG} \equal{} \frac{BF}{CE}.
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