MathDB
Putnam 2018 B4

Source:

December 2, 2018
PutnamPutnam 2018

Problem Statement

Given a real number aa, we define a sequence by x0=1x_0 = 1, x1=x2=ax_1 = x_2 = a, and xn+1=2xnxn1xn2x_{n+1} = 2x_nx_{n-1} - x_{n-2} for n2n \ge 2. Prove that if xn=0x_n = 0 for some nn, then the sequence is periodic.