MathDB
Sum of ni^n from 1 to 2002

Source:

April 6, 2013

Problem Statement

Find i+2i2+3i3+…+2002i2002i+2i^2+3i^3+\ldots+2002i^{2002}.
<spanclass=′latex−bold′>(A)</span>−999+1002i<spanclass=′latex−bold′>(B)</span>−1002+999i2<spanclass=′latex−bold′>(C)</span>−1001+1000i<span class='latex-bold'>(A) </span>-999+1002i\qquad<span class='latex-bold'>(B) </span>-1002+999i\sqrt2\qquad<span class='latex-bold'>(C) </span>-1001+1000i <spanclass=′latex−bold′>(D)</span>−1002+1001i<spanclass=′latex−bold′>(E)</span>i<span class='latex-bold'>(D) </span>-1002+1001i\qquad<span class='latex-bold'>(E) </span>i
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