MathDB
BQ = 2QC, CR = 2RA, < PRQ = 90^o , equal angles wanted

Source: Olimpíada de Mayo / Maio (May Olympiad) 2019 L2

July 11, 2019
geometryequal angles

Problem Statement

On the sides AB,BCAB, BC and CACA of a triangle ABCABC are located the points P,QP, Q and RR respectively, such that BQ=2QC,CR=2RABQ = 2QC, CR = 2RA and PRQ=90o\angle PRQ = 90^o. Show that APR=RPQ\angle APR =\angle RPQ.