In triangle ABC, AB=AC. If there is a point P strictly between A and B such that AP=PC=CB, then ∠A=
[asy]
draw((0,0)--(8,0)--(4,12)--cycle);
draw((8,0)--(1.6,4.8));
label("A", (4,12), N);
label("B", (0,0), W);
label("C", (8,0), E);
label("P", (1.6,4.8), NW);
dot((0,0));
dot((4,12));
dot((8,0));
dot((1.6,4.8));
[/asy]
<spanclass=′latex−bold′>(A)</span>30∘<spanclass=′latex−bold′>(B)</span>36∘<spanclass=′latex−bold′>(C)</span>48∘<spanclass=′latex−bold′>(D)</span>60∘<spanclass=′latex−bold′>(E)</span>72∘