The vertex E of a square EFGH is at the center of square ABCD. The length of a side of ABCD is 1 and the length of a side of EFGH is 2. Side EF intersects CD at I and EH intersects AD at J. If angle EID=60∘, the area of quadrilateral EIDJ is <spanclass=′latex−bold′>(A)</span>41<spanclass=′latex−bold′>(B)</span>63<spanclass=′latex−bold′>(C)</span>31<spanclass=′latex−bold′>(D)</span>42<spanclass=′latex−bold′>(E)</span>23