Let Q≥0 be the non-negative rational numbers, f:Q≥0→Q≥0 such that f(z+1)=f(z)+1, f(1/z)=f(z) for z=0, and f(0)=0. Define a sequence Pn of non-negative integers recursively via P_0 = 0, P_1 = 1, P_n = 2 P_{n-1}+P_{n-2} for every n≥2. Find f(P24P20).Proposed by Robert Trosten