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Inner product vector space

Source: Iran PPCE 2012-Linear Algebra exam-P6

February 16, 2012
vectorfunctioninvariantlinear algebralinear algebra unsolved

Problem Statement

Suppose that VV is a finite dimensional vector space over the real numbers equipped with an inner product and S:V×VRS:V\times V \longrightarrow \mathbb R is a skew symmetric function that is linear for each variable when others are kept fixed. Prove there exists a linear transformation T:VVT:V \longrightarrow V such that
u,vV:S(u,v)=<u,T(v)>\forall u,v \in V: S(u,v)=<u,T(v)>.
We know that there always exists vVv\in V such that W=<v,T(v)>W=<v,T(v)> is invariant under TT. (it means T(W)WT(W)\subseteq W). Prove that if WW is invariant under TT then the following subspace is also invariant under TT:
W={vV:uW<v,u>=0}W^{\perp}=\{v\in V:\forall u\in W <v,u>=0\}.
Prove that if dimension of VV is more than 33, then there exist a two dimensional subspace WW of VV such that the volume defined on it by function SS is zero!!!!
(This is the way that we can define a two dimensional volume for each subspace VV. This can be done for volumes of higher dimensions.)