MathDB
AJHSME 1991 Problem 7

Source:

June 24, 2011

Problem Statement

The value of (487,000)(12,027,300)+(9,621,001)(487,000)(19,367)(.05)\frac{(487,000)(12,027,300)+(9,621,001)(487,000)}{(19,367)(.05)} is closest to
(A) 10,000,000(B) 100,000,000(C) 1,000,000,000(D) 10,000,000,000(E) 100,000,000,000\text{(A)}\ 10,000,000 \qquad \text{(B)}\ 100,000,000 \qquad \text{(C)}\ 1,000,000,000 \\ \text{(D)}\ 10,000,000,000 \qquad \text{(E)}\ 100,000,000,000