MathDB
right angle leads to right angle, intersections of sides of cyclic ABCD related

Source: 2017 Singapore Seniors Round 2 p2

March 18, 2020
geometryright angleperpendicularcyclic quadrilateralCyclic

Problem Statement

In the cyclic quadrilateral ABCDABCD, the sides AB,DCAB, DC meet at QQ, the sides AD,BCAD,BC meet at P,MP, M is the midpoint of BDBD, If ∠APQ=90o\angle APQ=90^o, prove that PMPM is perpendicular to ABAB.
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