Inequality with 107/18
Source: JBMO Shortlist 2006
November 10, 2008
inequalitiesinequalities proposed
Problem Statement
Let be positive real numbers such that x\plus{}2y\plus{}3z\equal{}\frac{11}{12}. Prove the inequality 6(3xy\plus{}4xz\plus{}2yz)\plus{}6x\plus{}3y\plus{}4z\plus{}72xyz\le \frac{107}{18}.